Cisco India Conducted on 17th october at bangalore. There were 40 technical questions and 10 analytical questions. A total of 50 questions were provided.
Cisco Analytical questions: Mathematics – Geometry Questions:
-
Find perimeter of a trapezium with 3 sides given and distance between parallel sides given.
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A triangle ABC is given, a line DE is paralel to base side and that cuts the triangle. The ratio of area of triangle to the area of trapezium .given DE/BC=3/5.
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Four concentric circles are given. The radius of 1st circle is x.next is 2x,then 3x and 4x. given that area b/w 2nd and 1st is A and 4th and 3rd circles being B.find ratio of A to B
-
What is the Difference between the perimeteres of two concentric circles is 66. Find the difference between radius
answer 10.5 -
3/p=6,3/q=15. Find p-q
Cisco Technical questions
-
#define clrscr() 100
main()
{
clrscr();
printf(“%d”,clrscr());
} -
which of the followin is used for avoiding network congestion
bufferin
cachin
sourcequench
all of de above -
main()
{
int a;
printf(“%d”,scanf(%d,&a));
}
wats o/p of this pgm. What will b printed
ans :0 -
main()
{
printf(“as”);
printf(“\bhi”);
printf(“is\n”);
} wat will b printed. -
main()
{
unsigned short a=-1;
unsigned char b=a;
printf(“%d %d “,a,b);
}
wat is o/p of the program
a. 65535 -1
b. 65535 65535
c. -1 -1 -
arrays base address is 1000….array is a[5][4]..then wat is de
correct address of a[4][3]…
ans:1056 -
one packet is 64bytes..no of pkts send is 16000..then total no of bytes send is
ans 1024000 -
#define maxval 5 (programming / computer science engineering technical questions)
int main (void)
{
int i=1;
if(i-maxval)
{
printf(“inside”);
}
else
{
printf(“out”);
}
find o/p??? -
#define a 3+3
#define b 11-3
main()
{
printf(“%d”,a*b);
}
wat is o/p????? -
A question in which segment address is given. logical address is 800. Base addresses also given. You have 2 find physical address
-
There was a question on processor speed in nanocycles. Then it performs a instruction in x cycles. like this..
-
main()
{
int *i;
int s=(int *)malloc(10*sizeof(int));
for (i=0;i<10;i++)
{
printf(“%d”,i*i)
}
whats the output?
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